layui 实现自动选择radio单选框(checked)的方法

<div class="layui-form-item">
  <label class="layui-form-label">消息通知</label>
   <div class="layui-input-block">
    <input name="is_notice" value="1" type="radio" title="通知" checked="">
    <input name="is_notice" value="0" type="radio" title="不通知">
   </div>
</div>

$.get( 
  "{:url('user/xxxx')}",
  {'id':adminId},
  function(d){
    //设置是否通知
    if(d.is_notice == 0){
     $("input[name=is_notice][value=1]").prop("checked","false");
     $("input[name=is_notice][value=0]").prop("checked","true");
    }
    form.render(); //更新全部
   }
);