python 顺时针打印矩阵的超简洁代码

# -*- coding:utf-8 -*-
class Solution:
  # matrix类型为二维列表，需要返回列表
  def printMatrix(self, matrix):
    # write code here
    res=[]
    n=len(matrix)
    m=len(matrix[0])
    if m==1 and n==1:
      res=[matrix[0][0]]
      return res
    else:
      for o in range((min(m,n)+1)//2):
        [res.append(matrix[o][i]) for i in range(o,m-o)]
        [res.append(matrix[j][m-o-1]) for j in range(o,n-o) if matrix[j][m-o-1] not in res]
        [res.append(matrix[n-o-1][k]) for k in range(m-1-o,o-1,-1) if matrix[n-o-1][k] not in res]
        [res.append(matrix[l][o]) for l in range(n-1-o,o-1,-1) if matrix[l][o] not in res]
      return res