C++实现简单推箱子小游戏

#include<stdio.h>
#include<stdlib.h>
#include<getch.h>

int main(int argc,const char*argv[])
{
 int cut=0;
 int a[8][8]={
  {0,0,3,3,3,3,0,0}, 
  {0,0,3,5,5,3,0,0}, 
  {0,0,3,0,5,3,0,0}, 
  {0,3,0,0,4,5,3,0}, 
  {3,3,0,4,0,0,3,3}, 
  {3,0,0,3,4,4,0,3}, 
  {3,0,0,2,0,0,0,3}, 
  {3,3,3,3,3,3,3,3}}; 
 int x=6,y=3;
 for(;;)
 {
 int cunt=0;
 system("clear");
 for(int i=0;i<8;i++)
 {
 for(int j=0;j<8;j++)
 {
 if(a[i][j]==9)
 {
 cunt++;
 }
 switch(a[i][j])
 {
 case 0:printf(" ");break;
 case 2:printf("@ ");break;//人
 case 3:printf("# ");break;//墙
 case 4:printf("$ ");break;//箱子
 case 5:printf("o ");break;//目标位置
 case 7:printf("@ ");break;
 case 9:printf("$ ");break;
 }
 }
 printf("\n");
 }
 if(4==cunt)
 {
 printf("成功\n步数：%d",cut);
 return 0;
 }
 //根据数据的大小来判断当前的坐标上的情况
 switch(getch())
 {
 case 183:
  if(0!=x&&3==a[x-1][y])
 {
 a[x][y]=2;
 }
 else if(5==a[x-1][y]||0==a[x-1][y])
 {
 a[x][y]-=2;
 a[x-1][y]+=2;
 x--;
 cut++;
 }
 else if((5==a[x-2][y]||0==a[x-2][y])&&(4==a[x-1][y]||9==a[x-1][y]))
 {
 a[x-2][y]+=4;
 a[x-1][y]-=4;
 a[x-1][y]+=2;
 a[x][y]-=2;
 x--;cut++;
 }break;
 case 184:
 if(0!=x&&3==a[x+1][y])
 {
 a[x][y]=2;
 }
 else if((5==a[x+1][y])||(0==a[x+1][y]))
 {
 a[x][y]-=2;
 a[x+1][y]+=2;
 x++;cut++;
 }
 else if((5==a[x+2][y]||0==a[x+2][y])&&(4==a[x+1][y]||9==a[x+1][y]))
 {
 a[x+2][y]+=4;
 a[x+1][y]-=4;
 a[x+1][y]+=2;
 a[x][y]-=2;
 x++;cut++;
 }break;
 case 185:
  if(0!=x&&3==a[x][y+1])
 {
 a[x][y]=2;
 }
 else if(5==a[x][y+1]||0==a[x][y+1])
 {
 a[x][y]-=2;
 a[x][y+1]+=2;
 y++;cut++;
 }
 else if((0==a[x][y+2]||5==a[x][y+2])&&(4==a[x][y+1]||9==a[x][y+1]))
 {
 a[x][y+2]+=4;
 a[x][y+1]-=4;
 a[x][y+1]+=2;
 a[x][y]-=2;
 y++;cut++;
 }break;
 case 186:
  if(0!=x&&3==a[x][y-1])
 {
 a[x][y]=2;
 }
 else if(5==a[x][y-1]||0==a[x][y-1])
 {
 a[x][y]-=2;
 a[x][y-1]+=2;
 y--;cut++;
 }
 else if((0==a[x][y-2]||5==a[x-1][y])&&(4==a[x][y-1]||9==a[x][y-1]))
 {
 a[x][y-2]+=4;
 a[x][y-1]-=4;
 a[x][y-1]+=2;
 a[x][y]-=2;
 y--;cut++;
 }break;
 }
} 
}