C++实现接两个链表实例代码

#include <iostream> 
#include <string> 
#include <algorithm> 
using namespace std; 
typedef int ElemType; 
 
typedef struct Node 
{ 
  ElemType data; 
  struct Node *next; 
}Lnode,*LinkList; 
 
 
//打印  
void print(LinkList &head) 
{ 
  LinkList plist=head->next; 
  while(plist!=NULL) 
  { 
    cout<<plist->data<<" "; 
    plist=plist->next; 
  } 
  cout<<endl; 
} 
 
//逆序输入链表  
void CreateList(LinkList &L,int m) 
{ 
  LinkList p; 
  L=(LinkList)malloc(sizeof(Node)); 
  L->next=NULL; 
  cout<<"逆序输入元素，空格分隔:"<<endl; 
  for(int i=m;i>0;--i) 
  { 
    p=(LinkList)malloc(sizeof(Node)); 
    cin>>p->data; 
    p->next=L->next; 
    L->next=p; 
  } 
  print(L); 
} 
 
//连接链表  
void Combine(LinkList &ha,int m,LinkList &hb,int n,LinkList &hc) 
{ 
  LinkList selectMin; 
  hc=(LinkList)malloc(sizeof(Node)); 
  int flag=0; 
  if(m>n) 
  { 
    selectMin=hb; 
    flag=1; //ha在后面  
  } 
  else 
  selectMin=ha; 
   
  while(selectMin->next!=NULL) 
  selectMin=selectMin->next; 
   
  if(flag) 
  { 
    selectMin->next=ha->next; 
    hc=hb; 
    free(ha);//notice 
  } 
  else 
  { 
    selectMin->next=hb->next; 
    hc=ha; 
    free(hb); 
  } 
  cout<<"合并后的链表为："<<endl; 
  print(hc);  
} 
 
void Destory(LinkList &hc) //仅释放hc即可  
{ 
  LinkList temp; 
  while(hc!=NULL) 
  { 
    temp=hc; 
    hc=hc->next; 
    free(temp); 
  } 
} 
int main() 
{ 
  int m,n; 
  cout<<"请输入以ha为head节点链表的元素个数："<<endl; 
  cin>>m; 
  LinkList ha,hb,hc; 
  CreateList(ha,m); 
  cout<<"请输入以hb为head节点链表的元素个数："<<endl; 
  cin>>n; 
  CreateList(hb,n); 
  Combine(ha,m,hb,n,hc); 
   
  Destory(hc); 
  return 0;   
}