Python 获取项目根路径的代码

import sys
import os
class pathutil(object):
  """路径处理工具类"""
  def __init__(self):
    # 判断调试模式
    debug_vars = dict((a, b) for a, b in os.environ.items()
             if a.find('IPYTHONENABLE') >= 0)
    # 根据不同场景获取根目录
    if len(debug_vars) > 0:
      """当前为debug运行时"""
      self.rootPath = sys.path[2]
    elif getattr(sys, 'frozen', False):
      """当前为exe运行时"""
      self.rootPath = os.getcwd()
    else:
      """正常执行"""
      self.rootPath = sys.path[1]
    # 替换斜杠
    self.rootPath = self.rootPath.replace("\\", "/")
  def getPathFromResources(self, fileName):
    """按照文件名拼接资源文件路径"""
    filePath = "%s/resources/%s" % (self.rootPath, fileName)
    return filePath
PathUtil = pathutil()
if __name__ == '__main__':
  """测试"""
  # path = PathUtil.getPathFromResources("context.ini")
  print(PathUtil.rootPath)

import os

print '***获取当前目录***'
print os.getcwd()
print os.path.abspath(os.path.dirname(__file__))
# __file__ 为当前文件, 若果在ide中运行此行会报错,可改为 #d = path.dirname('.') 
# 但是改为.后，就是获得当前目录，接着使用dirname函数访问上级目录
print '***获取上级目录***'
print os.path.abspath(os.path.dirname(os.path.dirname(__file__)))
print os.path.abspath(os.path.dirname(os.getcwd()))
print os.path.abspath(os.path.join(os.getcwd(), ".."))
print '***获取上上级目录***'
print os.path.abspath(os.path.join(os.getcwd(), "../.."))