用python3 返回鼠标位置的实现方法(带界面)

#!/usr/bin/python3
# -*- coding: UTF-8 -*-

import time
import pyautogui as pag
import tkinter


def get():
  po.delete(0,tkinter.END)
	time.sleep(2) #几秒后返回位置
  x , y = pag.position()
  po.insert(0,str(x)+','+str(y))

root = tkinter.Tk()
tip = tkinter.Label(root,text="返回点击获取2s后的光标位置")
tip.grid(row=0)
po = tkinter.Entry(root)
po.grid(row=1)
do = tkinter.Button(root,text="获取",command=get) #点击获取位置
do.grid(row=2)


root.mainloop()

#!/usr/bin/python3
# -*- coding: UTF-8 -*-

import time
import pyautogui as pag
import tkinter

mytime = 2

#判断时间是否合法
def safe():			
	text = getmytime.get();
	#小数点个数
	point = 0
	if(text==""):
		return False
	for i in text:
		if(i>='0' and i<='9'and point<2):
			continue
		elif(i=='.'):
			point = point + 1
		else:
			return False
	return True
def get():
	global mytime
	if(safe()):
		mytime = float(getmytime.get())
		
		#不知道为何下面的这个if没用
		if(mytime>7.0):
			showpos.delete(0,tkinter.END)
			showpos.insert(0,"请耐心等候")
	
		time.sleep(mytime) #几秒后返回位置
		x , y = pag.position()
		showpos.delete(0,tkinter.END)
		showpos.insert(0,str(x)+','+str(y))
	else:
		showpos.delete(0,tkinter.END)
		showpos.insert(0,"输入非法哟~")

 
root = tkinter.Tk()
root.resizable(0,0)

tip1 = tkinter.Label(root,text="点击按钮获取")
tip1.place(relx=0.1,rely=0.1)
getmytime = tkinter.Entry(root,width=3)
getmytime.place(relx=0.6,rely=0.1)
getmytime.insert(0,str(mytime))
tip2 = tkinter.Label(root,text="s后的")
tip2.place(relx=0.8,rely=0.1)

tip3 = tkinter.Label(root,text="光标位置:")
tip3.place(relx=0.1,rely=0.3)
showpos = tkinter.Entry(root,width=10)
showpos.place(relx=0.5,rely=0.3)
do = tkinter.Button(root,text="按钮",command=get) #点击获取位置
do.place(relx=0.8,rely=0.6)


root.mainloop()