本文实例讲述了python实现在无须过多援引的情况下创建字典的方法。分享给大家供大家参考。具体实现方法如下：
1.使用itertools模块
import itertools the_key = ['ab','22',33] the_vale = ['aaaa',"dddddddd",'22222222222'] d = dict(itertools.izip(the_key,the_vale)) print d
2.加参数
dict = dict(red = 1,bule = 2,yellow = 3) print dict
结果为：{'yellow': 3, 'bule': 2, 'red': 1}
3.使用内置的zip函数
zip([iterable,...])返回一个列表，
the_key = ['ab','22',33] the_vale = ['aaaa',"dddddddd",'22222222222'] dict2 = dict(zip(the_key,the_vale)) print type(zip(the_key,the_vale)) print dict2
结果：
<type 'list'>
{33: '22222222222', 'ab': 'aaaa', '22': 'dddddddd'}
4.dict的fromkeys函数
创建的每个键有相同的value
fromkeys(seq[,value]) Create a new dictionary with keys from seq and values set to value. the_key = ['ab','22',33] the_vale = 0 d = dict.fromkeys(the_key,the_vale) print
结果：{33: 0, 'ab': 0, '22': 0}
import string count_by_letter = dict.fromkeys(string.ascii_lowercase,0) print count_by_letter
结果：
{'a': 0, 'c': 0, 'b': 0, 'e': 0, 'd': 0, 'g': 0, 'f': 0, 'i': 0, 'h': 0, 'k': 0, 'j': 0, 'm': 0, 'l': 0, 'o': 0, 'n': 0, 'q': 0, 'p': 0, 's': 0, 'r': 0, 'u': 0, 't': 0, 'w': 0, 'v': 0, 'y': 0, 'x': 0, 'z': 0}
希望本文所述对大家Python程序设计的学习有所帮助。
