thinkPHP简单实现多个子查询语句的方法

SELECT a.*,b.* from (SELECT a.id as opener_id,a.name,sum(c.money) as bonus_money,c.year,c.month from sh_opener a
LEFT JOIN sh_opener_bonus b on a.id = b.opener_id
LEFT JOIN sh_incentive c on b.incentive_id = c.id
where a.agent_id = 3 and a.status = 1 and c.year = 2015 and c.month = 11
GROUP BY a.id,c.year,c.month) a
LEFT JOIN (SELECT a.id as payment_id,a.opener_id,a.money as payment_money,a.trode_number from sh_opener_bonus_payment a
where a.year = 2015 and a.`month` = 11 and a.agent_id = 3) b
on a.opener_id = b.opener_id;

$useYear = date('Y',strtotime('last month'));
$this->assign('useYear',$useYear);
$useMonth = date('m',strtotime('last month'));
$this->assign('useMonth',$useMonth);
// 获取上一月人员的奖金金额
// 子查询1
$whereSub1['a.agent_id'] = $this->agent_id;
$whereSub1['a.status'] = 1;
$whereSub1['c.year'] = $useYear;
$whereSub1['c.month'] = $useMonth;
$subQuery1 = M()->table('sh_opener a')->join('sh_opener_bonus b on a.id = b.opener_id')->join('sh_incentive c on b.incentive_id = c.id')->where($whereSub1)->group('a.id,c.year,c.month')->field('a.id,a.name,sum(c.money) as bonus_money,c.year,c.month')->select(false);
// 子查询2
$whereSub2['a.agent_id'] = $this->agent_id;
$whereSub2['a.year'] = $useYear;
$whereSub2['a.month'] = $useMonth;
$subQuery2 = M()->table('sh_opener_bonus_payment a')->where($whereSub2)->field('a.id as payment_id,a.opener_id,a.money as payment_money,a.trode_number')->select(false);
$list = M()->table($subQuery1.' a')->join($subQuery2.' b on a.id = b.opener_id')->select();
$this->assign('list',$list);