上一篇文章写到原生js取代jquery的一些常用函数：原生js仿jquery一些常用方法，那么，ajax如何实现呢？如下是一个比较完整的ajax()
function ajax(){
var ajaxData = {
type:arguments[0].type || "GET",
url:arguments[0].url || "",
async:arguments[0].async || "true",
data:arguments[0].data || null,
dataType:arguments[0].dataType || "text",
contentType:arguments[0].contentType || "application/x-www-form-urlencoded",
beforeSend:arguments[0].beforeSend || function(){},
success:arguments[0].success || function(){},
error:arguments[0].error || function(){}
}
ajaxData.beforeSend()
var xhr = createxmlHttpRequest();
xhr.responseType=ajaxData.dataType;
xhr.open(ajaxData.type,ajaxData.url,ajaxData.async);
xhr.setRequestHeader("Content-Type",ajaxData.contentType);
xhr.send(convertData(ajaxData.data));
xhr.onreadystatechange = function() {
if (xhr.readyState == 4) {
if(xhr.status == 200){
ajaxData.success(xhr.response)
}else{
ajaxData.error()
}
}
}
}
function createxmlHttpRequest() {
if (window.ActiveXObject) {
return new ActiveXObject("Microsoft.XMLHTTP");
} else if (window.XMLHttpRequest) {
return new XMLHttpRequest();
}
}
function convertData(data){
if( typeof data === 'object' ){
var convertResult = "" ;
for(var c in data){
convertResult+= c + "=" + data[c] + "&";
}
convertResult=convertResult.substring(0,convertResult.length-1)
return convertResult;
}else{
return data;
}
}
使用格式跟jquery的ajax差不多：
ajax({
type:"POST",
url:"ajax.php",
dataType:"json",
data:{"val1":"abc","val2":123,"val3":"456"},
beforeSend:function(){
//some js code
},
success:function(msg){
console.log(msg)
},
error:function(){
console.log("error")
}
})
以上就是小编为大家带来的原生js实现ajax方法(超简单)的全部内容了，希望对大家有所帮助，多多支持脚本之家~
