jQuery模拟黑客帝国矩阵效果实例

<div id="container">
  <div style="width:10px; word-break :break-all">
    10001001110010010010000
  </div>
  <div style="width:10px; word-break :break-all;margin-left:30px">
    the answer is in your mind
  </div>
</div>

#container div{padding:10px;position:absolute;border:0px dotted brown;width:0px;color:green;text-shadow: 1px 1px 3px #cccccc;}
.text{padding:10px;color:#ccc;}
#panel{width:400px;margin:0 auto;color:white;margin-top:20%;font-size:15px;font-weight:bold;z-index:99999;background:black;}

$(function() {
  for (var i = 0; i < 3; i++) $('div', '#container').clone().prependTo('#container');
  //克隆一遍增加数据
  range();
  setInterval(drop, 150); //速度150毫秒
});
//排列
function range() {
  var num = 1;
  $('div', '#container').each(function(i) {
    var ww = $(window).width(); //窗口宽度
    var wh = $(window).height();
    var ol = $(this).offset().left; //距左边像素
    var ot = -20; //$(this).offset().top;//从头部以上开始
    i++;
    if (i % 22 == 0) num = 1; //22个一排
    $(this).css({
      "left": (ol + num * 60) + "px",
      "top": (ot + Math.ceil(i / 2) * 30) + "px"
    }); //距左距离保持，距上距离变化
    num++;
  });
}
//降落
function drop() {
  $('div', '#container').each(function(i) {
    var wh = $(window).height();
    var ol = $(this).offset().left;
    var ot = $(this).offset().top;
    var rnd = Math.round(Math.random() * 100);
    var rnd2 = Math.round(Math.random() * 50);
    //i = i == 0 ? 0.5 : i;
    $(this).css({
      "top": (ot + rnd + rnd2) + "px"
    }); //降落的速度
    if (ot >= wh) //如果掉到窗口以下
    {
      //$(this).css({"top":wh-20 +"px"});
      //停在当前位置不让继续从上往下掉
      $(this).css({
        "top": -5 * rnd + "px"
      }); //从顶部以上开始
    }
  });
}