在做页面时，用户要求，不同的分辨率，弹出窗口的位置不同，我想是不是先获得屏幕宽度，然后付值给变量，再在onclick中设置参数
<script>
alert(screen.width+"*"+screen.height)
</script>
<script>
function centerWindow(url,w,h){
l=(screen.width-w)/2
t=(screen.height-h)/2
window.open(url,'','left='+l+',top='+t+',width='+w+',height='+h)
}
</script>
<input type=button onclick="centerWindow('about:blank',200,200)">
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<body>
<SCRIPT LANGUAGE="JavaScript">
var s ="网页可见区域宽："+ document.body.clientWidth;
s+="\r\n网页可见区域高："+ document.body.clientHeight;
s += "\r\n网页正文全文宽："+ document.body.scrollWidth;
s += "\r\n网页正文全文高："+ document.body.scrollHeight;
s += "\r\n网页正文部分上："+ window.screenTop;
s += "\r\n网页正文部分左："+ window.screenLeft;
s += "\r\n屏幕分辨率的高："+ window.screen.height;
s += "\r\n屏幕分辨率的宽："+ window.screen.width;
s +="\r\n屏幕可用工作区高度："+ window.screen.availHeight;
s +="\r\n屏幕可用工作区宽度："+ window.screen.availWidth;
alert(s);
</SCRIPT>
---------------------------------------------------------------
<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
function redirectPage() {
/*var url640x480 = "http://www.yourweb.com/640x480.html";**记得改相应的页面*/
var url800x600 = "index1.asp";
var url1024x768 = "index2.asp";
/*if ((screen.width == 640) && (screen.height == 480))
window.location.href= url640x480;*/
if (screen.width <= 800 )
window.location.href= url800x600;
else if ((screen.width >= 1024) )
window.location.href= url1024x768;
}
// End -->
</script>
这段代码是根据不同的屏幕显示不同的页面
下面是传递这个参数的
<script language=JavaScript>
document.write("<a href='WebStat/index.asp'>");
document.write("<img src='WebStat/count.asp?Referer=<%=refer%>
&Width="+escape(screen.width)+"&Height="+escape(screen.height)+
"' border=0 width=1 height=1>");
document.write("</a>");
</script>
