java的arraylist排序示例(arraylist用法)

package com.yonyou.test;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class Test {
 public static void main(String[] args) {
  Student zlj = new Student("丁晓宇", 21);
  Student dxy = new Student("赵四", 22);
  Student cjc = new Student("张三", 11);
  Student lgc = new Student("刘武", 19);
  List<Student> studentList = new ArrayList<Student>();
  studentList.add(zlj);
  studentList.add(dxy);
  studentList.add(cjc);
  studentList.add(lgc);
  System.out.println("按照年齡排序：");
  Collections.sort(studentList, new SortByAge());
  for (Student student : studentList) {
   System.out.println(student.getName() + " / " + student.getAge());
  }
  System.out.println(" ========= ");
  System.out.println("按照姓名排序");
  Collections.sort(studentList, new SortByName());
  for (Student student : studentList) {
   System.out.println(student.getName() + " / " + student.getAge());
  }
 }
}
class SortByAge implements Comparator {
 public int compare(Object o1, Object o2) {
  Student s1 = (Student) o1;
  Student s2 = (Student) o2;
  if (s1.getAge() > s2.getAge())
   return 1;
  else if (s1.getAge() == s2.getAge()) {
   return 0;
  }
  return -1;
 }
}
class SortByName implements Comparator {
 public int compare(Object o1, Object o2) {
  Student s1 = (Student) o1;
  Student s2 = (Student) o2;
  if(s1.getName().compareTo(s2.getName()) < 0)
   return -1;
  else if (s1.getName().compareTo(s2.getName()) > 0) {
   return 1;
  }
  return 0;
 }
}
class Student{
 private int age;
 private String name;
 public int getAge() {
  return age;
 }
 public void setAge(int age) {
  this.age = age;
 }
 public String getName() {
  return name;
 }
 public void setName(String name) {
  this.name = name;
 }
 public Student(String name,int age) {
  this.age = age;
  this.name = name;
 }
}