本文实例讲述了jquery访问servlet并返回数据到页面的方法。分享给大家供大家参考。具体实现方法如下：
1. servlet:AjaxServlet.java如下：
import java.io.IOException;
import java.io.PrintWriter;
import java.net.URLDecoder;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class AjaxServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doGet(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
Integer total = (Integer) req.getSession().getAttribute("total");
int temp = 0;
if(total == null ){
temp = 1;
}else{
temp = total.intValue() + 1;
}
req.getSession().setAttribute("total",temp);
try {
//1.取参数
resp.setContentType("text/html;charset=GBK");
PrintWriter out = resp.getWriter();
String old = req.getParameter("name");
//2.检查参数是否有问题
//String name = new String(old.getBytes("iso8859-1"),"UTF-8");
String name = URLDecoder.decode(old,"UTF-8");
if("".equals(old) || old == null){
out.println("用户名必须输入");
}else{
if("liling".equals(name)){
out.println("恭喜登录成功");
return;
}else{
out.println("该用户名未注册，您可以注册["+name+"]这个用户名"+temp);
}
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
//3.检验操作
}
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
doGet(req, resp);
}
}
2. verify.js如下：
3. 前台页面如下：
希望本文所述对大家的Ajax程序设计有所帮助。
